Question:
How to find MinDiff() in two arrays?

Summary:

Suppose we have N and M as input parameters and return the minimum possible difference between the maximum and minimum number.


Our task is to complete the function findMinDiff(), which takes array A[ ], 


Solution:

class Solution{

    public:

    long long findMinDiff(vector<long long> a, long long n, long long m){

    //code

       sort(a.begin(),a.end());

       long long start=0,end=m-1;

       long long min_len=INT_MAX;

       long long dif=0;

       while(end<n){

           dif=a[end++]-a[start++];

           min_len=min(min_len,dif);

           

       }

       return min_len;

    }   

};


Explanation:

  • The method findMinDiff takes three parameters: a vector a of long long integers, representing a sequence of numbers, n representing the size of the sequence, and m representing the number of elements to consider at a time.

  • Inside the method:

    • The sort function from the algorithm library is used to sort the input vector a in ascending order.

    • Variables start and end are initialized to 0 and m - 1 respectively. These variables represent the start and end indices of the subsequence currently being considered.

    • A variable min_len is initialized to the maximum possible value of a long long integer (INT_MAX), which is used to keep track of the minimum difference found between elements of the subsequence.

    • A variable dif is initialized to 0, which will store the difference between the current end and start elements of the subsequence.

    • A while loop runs as long as the end index is less than n. Within this loop:

      • The difference between the element at the current end index and the element at the current start index is calculated and stored in dif.

      • The minimum of the current min_len and dif is computed and stored back into min_len.

      • The start and end indices are incremented to slide the window to the right by one position.

  • Once the loop ends, the minimum difference (min_len) found among all the subsequences is returned.


Overall, this code efficiently finds the minimum difference between any two elements when considering subsequences of size m from the input sequence a.


Suggested blogs:

>Python Error Solved: load_associated_files do not load a txt file

>Python Error Solved: pg_config executable not found

>Set up Node.js & connect to a MongoDB Database Using Node.js

>Setting up a Cloud Composer environment: Step-by-step guide

>What is microservice architecture, and why is it better than monolithic architecture?

>What is pipe in Angular?

>What makes Python 'flow' with HTML nicely as compared to PHP?

>What to do when MQTT terminates an infinite loop while subscribing to a topic in Python?

>Creating custom required rule - Laravel validation

>How to configure transfers for different accounts in stripe with laravel?


Ritu Singh

Ritu Singh

Submit
0 Answers