Question:

How to make an Array of distinct digits from a mixed array?

Summary:

We have an array of N lengths with all positive integers in it. We have to find all distinct digits present in the array and create a new array of numbers using Java.

Here we are taking an array of integers (nums) as input and returning an array containing unique digits present across all the numbers. Here's a detailed explanation:

Solution:

//User function Template for Java

class Solution

{

public int[] common_digits(int[] nums)

{

// {111, 222, 333, 4444, 555, 666};

// {1, 2, 3, 4, 5, 6}

Set<Integer> set = new HashSet<>();

for(int i=0; i<nums.length; i++) {

while(nums[i] > 0) {

int currEle = nums[i] % 10;

nums[i] = nums[i] / 10;

set.add(currEle);

}

int[] res = new int[set.size()];

int k = 0;

for(Integer i: set) {

res[k++] = i;

}

return res;

}

Explanation:

The method uses a HashSet (set) to store unique digits encountered across all numbers.
It iterates through each number in the array (nums).
Inside the loop, it extracts individual digits from the current number by repeatedly dividing by 10 and adding the remainder to the set.
The set ensures that only unique digits are stored.
Finally, it creates a new array (res) to store the unique digits and populates it by converting the set to an array.

Example:

If the input array nums is [111, 222, 333, 4444, 555, 666], the method would return an array [1, 2, 3, 4, 5, 6], representing the unique digits present across all numbers.

Answered By: >riteshsinharts221

Credit: >Geeksforgeeks

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