Question:

How to count odd and even number from a series?

Summary:

Suppose we have an array of N elements in it. We have to separate the odd and even elements form the array separately using java.

Solution:

//User function Template for Java

class Solution

{

public int[] countOddEven(int[] arr, int n)

{

int [] result = new int[2];

int odd = 0, even = 0;

for (int i : arr) {

if (i%2 == 0)

even++;

else

odd++;

}

result[0] = odd;

result[1] = even;

return result;

}

Explanation:

This Java code defines a class named Solution with a public method countOddEven, which takes an array of integers arr and its length n as parameters. Inside the method:

It initializes an integer array result of size 2 to store the count of odd and even numbers.
It initializes two variables odd and even to store the count of odd and even numbers, respectively.
It iterates through each element of the input array arr.
For each element, it checks if it's even (i % 2 == 0). If so, it increments the even count; otherwise, it increments the odd count.
After iterating through all elements, it assigns the counts of odd and even numbers to the respective indices of the result array.
Finally, it returns the result array containing the counts of odd and even numbers.

In summary, this code calculates the counts of odd and even numbers in an input array and returns an array containing these counts.

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