Question:

Rearrange numbers of an array alternatively, with Javascript

Summary:

Suppose, we have an array of positive integers. We have to rearrange the array elements alternatively in a way that the first element of the array should be the largest number and the second should be the the smallest one. third should be second max, fourth should be second min, and so on.

Solution:

//User function Template for javascript

/**

* @param {number[]} arr

* @param {number} n

class Solution {

//Function to rearrange the array elements alternately.

rearrange(arr, n){

// code here

let minIndex = 0

let maxIndex = n - 1

let maxEle = arr[maxIndex] + 1

for (let i = 0; i < n; i++) {

if (i % 2 === 0) {

arr[i] += (arr[maxIndex] % maxEle) * maxEle

maxIndex--

} else {

arr[i] += (arr[minIndex] % maxEle) * maxEle

minIndex++

}

for (let i = 0; i < n; i++) {

arr[i] = Math.floor(arr[i] / maxEle)

}

Explanation:

This JavaScript code defines a class Solution with a method rearrange to rearrange the elements of an array alternately.

rearrange Function:

It takes an array arr and its length n as parameters.
The function initializes minIndex to 0 and maxIndex to n - 1.
It calculates maxEle as the maximum element in the array plus 1.
Then, it iterates through the array using a loop.
For each iteration:
If the index is even, it modifies the current element by adding the remainder of the maximum element divided by maxEle multiplied by maxEle, and then decrements maxIndex.
If the index is odd, it modifies the current element by adding the remainder of the minimum element divided by maxEle multiplied by maxEle, and then increments minIndex.
After the loop, it iterates through the array again to update each element by dividing it by maxEle, effectively rearranging the elements alternately.

Overall, this function rearranges the elements of the array alternately based on the minimum and maximum elements, ensuring the desired pattern in the resulting array.

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