How to solve problems with Python syntax while writing a calculator app?

Question:

Handling user input and carrying out arithmetic operations are necessary when developing a simple calculator application in Python. This is a basic illustration of a command-line calculator application that can perform addition, subtraction, multiplication, and division, among other fundamental arithmetic operations. Invalid input error handling will also be included.

def add(x, y):

return x + y

def subtract(x, y):

return x - y

def multiply(x, y):

return x * y

def divide(x, y):

if y == 0:

raise ValueError("Division by zero is not allowed")

return x / y

while True:

print("Options:")

print("Enter 'add' for addition")

print("Enter 'subtract' for subtraction")

print("Enter 'multiply' for multiplication")

print("Enter 'divide' for division")

print("Enter 'quit' to end the program")

user_input = input(": ")

if user_input == "quit":

break

elif user_input in ("add", "subtract", "multiply", "divide"):

try:

num1 = float(input("Enter first number: "))

num2 = float(input("Enter second number: "))

if user_input == "add":

print("Result:", add(num1, num2))

elif user_input == "subtract":

print("Result:", subtract(num1, num2))

elif user_input == "multiply":

print("Result:", multiply(num1, num2))

elif user_input == "divide":

print("Result:", divide(num1, num2))

except ValueError:

print("Invalid input. Please enter valid numbers.")

else:

print("Invalid input. Please enter a valid option.")

In this code snippet:

The four fundamental arithmetic operations—add, subtract, multiply, and divide—are defined as functions.

The calculator is kept running indefinitely until the user decides to stop it using a "while" loop.

We give the user options and solicit their input inside the loop.

After processing user input and carrying out the chosen action, we show the outcome. To handle situations like division by zero or incorrect input, we also include error handling.

This code can be used as follows: